If the sum of the 2nd and 6th digits in the identification code equals 8, how many possibilities exist for these digits?

To determine the number of possibilities for the 2nd and 6th digits of the identification code, given that their sum equals 8, we can break it down as follows:

The digits in question can be any digits from 0 to 9. Specifically, we want to find pairs of digits (a) (the 2nd digit) and (b) (the 6th digit) such that (a + b = 8).

The valid pairs of digits that satisfy this equation are:

• (0, 8)

• (1, 7)

• (2, 6)

• (3, 5)

• (4, 4)

• (5, 3)

• (6, 2)

• (7, 1)

• (8, 0)

Each of these pairs consists of two digits, and both digits are in the range from 0 to 9.

There are a total of 9 pairs that meet the condition (a + b = 8). Since the digits can be arranged in two different ways (i.e., ( (a, b) ) and ( (b, a) ), except in the case